The electronic configuration of flourine elements respectively are :

a. $1 s^{2}$
b. $1 s^{2} 2 s^{2} 2 p^{2}$
c. $1 s^{2} 2 s^{2} 2 p^{5}$
d. $1 s^{2} 2 s^{2} 2 p^{4}$

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Solution

The correct option is B c
Fluorine has the electronic configuration of $1 s^{2} 2 s^{2} 2 p^{5}$ .

Therefore, option C is correct.

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Similar questions

Q. Electronic configurations of four elements

A, B, C

and

D

are given below:
(A)

1 s^{2} 2 s^{2} 2 p^{6}

(B)

1 s^{2} 2 s^{2} 2 p^{4}

(C)

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

(D)

1 s^{2} 2 s^{2} 2 p^{5}

Which of the following is the correct order of increasing tendency to gain electron?

Q. The electronic arrangements of four elements i, ii, iii, iv are:
(i)

1 s^{2}

(ii)

1 s^{2} 2 s^{2} 2 p^{2}

(iii)

1 s^{2} 2 s^{2} 2 p^{5}

(iv)

1 s^{2} 2 s^{2} 2 p^{6}

The tendency to form ionic bond is maximum in:

Electronic configuration of four elements A, B, C, and D are given below
A. $1 s^{2} 2 s^{2} 2 p^{6}$ B. $1 s^{2} 2 s^{2} 2 p^{4}$ C. $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
D. $1 s^{2} 2 s^{2} 2 p^{5}$
Whilch of the following is the correct order of increasing tendency to gain electron?
(a) A < C <B <D (b) A < B < C < D (c) D <B < C < A (d) D < A < B <C

Q. The electronic configuration of two neutral elements A and B are

A = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

and

B = 1 s^{2} 2 s^{2} 2 p^{5}

. Which type of compound they form?

Arrange the elements with the following electronic configurations in the increasing order of electron affinity

(i) $1 s^{2} 2 s^{2} 2 p^{3}$ (ii) $1 s^{2} 2 s^{2} 2 p^{4}$ (iii) $1 s^{2} 2 s^{2} 2 p^{5}$ (iv) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$

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The electronic configuration of flourine elements respectively are :a. 1s2b. 1s22s22p2c. 1s22s22p5d. 1s22s22p4

The correct option is B c Fluorine has the electronic configuration of 1s22s22p5. Therefore, option C is correct.

The electronic configuration of flourine elements respectively are :

a. $1 s^{2}$
b. $1 s^{2} 2 s^{2} 2 p^{2}$
c. $1 s^{2} 2 s^{2} 2 p^{5}$
d. $1 s^{2} 2 s^{2} 2 p^{4}$

The correct option is B c
Fluorine has the electronic configuration of $1 s^{2} 2 s^{2} 2 p^{5}$ .

Therefore, option C is correct.