The electronic configuration of four elements are given below. Which element does not belong to same family as others?

[Xe] 6 s^{2} 4 f^{14} 5 d^{10}

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[Kr] 5 s^{2} 4 d^{10}

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[Ne] 3 s^{2} 3 p^{5}

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[Ar] 4 s^{2} 3 d^{10}

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Solution

The correct option is C $[Ne] 3 s^{2} 3 p^{5}$
Elements having the same number of valence electrons belong to the same group.
$[Xe] 6 s^{2} 4 f^{14} 5 d^{10}$ , $[Kr] 5 s^{2} 4 d^{10}$ and $[Ar] 4 s^{2} 3 d^{10}$ belong to the same group since each one of them have two electrons in the outermost shell. In contrast, $[Ne] 3 s^{2} 3 p^{5}$ has 7 electrons in the outermost shell. Hence, it belongs to a different group.

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