The electronic configuration of Na+ ion is 2, 8.True or False.
A
True
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B
False
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Solution
The correct option is A
True
Atomic number of sodium = 11
Therefore number of electrons = 11
A positively charged ion, Na+ is formed by the removal of 1 electron from a sodium atom.So, sodium ion has 11-1 = 10 electrons in it.Thus,The electronic configuration of Na+ ion is 2, 8.