The electronic configuration of sodium atom is 2- 8- 1 and chlorine atom is 2- 8- 7- The atoms will form a nbsp- nbsp-bond by nbsp-of electrons- nbsp-covalentionicsharingtransferring

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Ionic Bonding

The electroni...

Question

The electronic configuration of sodium atom is 2, 8, 1 and chlorine atom is 2, 8, 7. The atoms will form a bond by of electrons.

covalent

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ionic

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sharing

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transferring

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Solution

The correct options are
B ionic
D transferring
The electronic configuration of sodium atom is 2, 8, 1, hence, it has 1 valence electron. Chlorine atom has 7 valence electrons and its electronic configuration is 2. 8, 7.

When sodium ( $N a$ ) and chlorine ( $C l$ ) combine, the sodium atom loses an electron to form $N a^{+}$ , and the chlorine atoms gain an electron to form $C l^{-}$ .

These oppositely charged ions are held together by the electrostatic force of attraction called ionic bond.

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Q. The electronic configuration of sodium atom is 2, 8, 1 and chlorine atom is 2, 8, 7. The atoms will form a bond by of electrons.

Electronic configuration of an atom X is (2, 8, 7). It combines with another atom Y having electronic configuration (.., 1).

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Q. Sodium atom with electronic configuration 2, 8, 1 achieves stable electronic configuration by -------- one electron from its outer shell.

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