The electronic configuration of some neutral atoms are given below :-
1. $1 s^{2} 2 s^{1}$
2. $1 s^{1} 2 s^{2} 2 p^{3}$
3. $1 s^{2} 2 s^{2} 2 p^{5}$
4. $1 s^{2} 2 s^{2} 2 p^{6} {3 s}^{1}$
Which of the following is the electronic configuration of fluorine?

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Solution

The correct option is A 3
Fluorine is the ninth element with a total of 9 electrons. In writing the electron configuration for fluorine the first two electrons will go in the $1 s$ orbital. Since $1 s$ can only hold two electrons the next 2 electrons for F go in the $2 s$ orbital.The remaining five electrons will go in the $2 p$ orbital.

Therefore electronic configuration of F = $1 s^{2} 2 s^{2} 2 p^{5}$ .

Hence,option A is correct answer.

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Similar questions

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{3}

Electronic configuration of four neutral atoms are given below.

Which of the following elements would not be paramagnetic

A, B, C

D

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{4}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6}

X

[N e] 3 s^{1}

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