The electronic configuration of some neutral atoms are given below
(1) $1 s^{2} 2 s^{1}$
(2) $1 s^{2} 2 s^{2} 2 p^{3}$
(3) $1 s^{2} 2 s^{2} 2 p^{4}$
(4) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$ .

In which of these electronic configuration would you expect to have highest
(i) $I E_{1}$ (ii) $I E_{2}$

3, 1

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2, 1

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3, 2

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2, 4

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Solution

The correct option is B 2, 1
More stable the configuration higher is its ionisation enthalpy.

(i) We know that half-filled orbital is more stable than a partially filled orbital. In option (2) 2p-orbital is half-filled, thus it has the highest IE₁.

(ii) After the removal of 1e⁻ from each of the following the option (1) and (4) attains the stable noble gas configuration (of helium and neon respectively) but the removal of e⁻ from 1s² requires more energy than in the case of 2p⁶ because 2p is in higher energy level. Thus, option (1) has the highest IE₂.

Hence, option B is correct.

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Similar questions

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{3}

Electronic configuration of four neutral atoms are given below.

Which of the following elements would not be paramagnetic

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{6} 4 s^{1}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

1 s^{2} 2 s^{2} 2 p^{3}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

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