The electronic configuration of sulphur is :

K (2), L (8), M (6)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

K (2), L (8), M (8)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K (2), L (6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K (2), L (8)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $K (2), L (8), M (6)$
Atomic number of sulphur = $16$
Therefore number of electrons = $16$
Thus, electronic configuration of sulphur $K (2), L (8), M (6)$
Number of orbit in sulphur = $3$

Suggest Corrections

Similar questions

\frac{k^{2} + 13 k + 42}{k^{2} + 15 k + 56}

\frac{k^{2} + 8 k}{k^{2} + 11 k + 30}

If $s e c θ + t a n θ = k, c o s θ =$

Two gaseous equilibria $S O_{2} (g) + 0.5 O_{2} (g) ⇌ S O_{3} (g)$ and

$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$ have equilibrium constants $K_{1}$ and $K_{2}$ respectively

at 298K. Which of the following relationships between $K_{1}$ and $K_{2}$ is correct

Equilibrium constants $K_{1}$ and $K_{2}$ for the following equilibria are

$N O (g) + 0.5 O_{2} (g) \to K_{1} N O_{2} (g)$ and
$2 N O_{2} (g) \to K_{2} 2 N O (g) + O_{2} (g)$

K_{1}

K_{2}

Join BYJU'S Learning Program