The electronic configuration of the atom of an element X is 2, 8, 4. In the modern periodic table, the element X is placed in :

$(a) 2^{n d} g r o u p$ $(b) 4^{t h} g r o u p$ $(c) 14^{t h} g r o u p$ $(d) 8^{t h} g r o u p$

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Solution

(c) $14^{t h} g r o u p$

Group number $= 10 + 4 = 14$

Hence, the element X is placed in the $14^{t h} g r o u p$ .

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X

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