Question

The electronic configuration of the Mn${}^{4+}$ ion is:

• A. $\left[Ar\right]$ 3d${}^4$ 4s${}^0$
• B. $\left[Ar\right]$ 3d${}^2$ 4s${}^1$
• C. $\left[Ar\right]$ 3d${}^1$ 4s${}^2$
• D. $\left[Ar\right]$ 3d${}^3$ 4s${}^2$

Answer 1

The correct option is D $\left[Ar\right]$ 3d${}^3$ 4s${}^2$

Mn (Z=25) has electronic configuration $\left[Ar\right]3d^{5}4s^2$.
When 4 electrons are lost, $M{n}^{4+}$ ion is obtained with electronic configuration $\left[Ar\right]3d^{3}4s^2$.