Question

Question 21

The electronic configuration of the outer most shell of the most electronegative elements is

(a) $2s^{2}2p^5$

(b) $3s^{2}3p^5$

(c) $4s^{2}4p^5$

(d) $5s^{2}5p^5$

Answer 1

The electronic configuration represents

$2s^{2}2p^5$ = Fluorine

$3s^{2}3p^5$ = Chlorine

$4s^{2}4p^5$ = Bromine

$5s^{2}5p^5$ = Iodine

Fluorine is most electronegativity element. Therefore, the answer is (a). $2s^{2}2p^5$