Question

The electronic configuration of the outermost orbit in the case of alkaline earth metal is:

• A. $n{s}^2$
• B. $n{s}^{2}n{p}^1$
• C. $n{s}^1$
• D. $n{s}^{2}n{p}^4$

Answer 1

The correct option is A $n{s}^2$

As there are two electrons are present in outermost orbital so its general outer electronic configuration is $n{s}^2$
Hence options (a) is correct.