Question

The electronic configuration of the outermost shell of the most electronegative element is

• A. $5s^{2}5p^5$
• B. $2s^{2}2p^5$
• C. $3s^{2}3p^5$
• D. $4s^{2}4p^5$

Answer 1

The correct option is B $2s^{2}2p^5$

Solution:

Fluorine is the most electronegative element, as its electronegativity is 4 (based on the pauling scale).

The atomic number of fluorine is 9

The electronic configuration of fluorine is $1s^{2}2s^{2}2p^5.$

Outermost shell electronic configuration of fluorine is $2s^{2}2p^5.$

Hence, correct option is (A).