Question

The electronic configuration, total spin, magnetic moment and unpaired electrons of the following are
(a)${}_{44}\text{Ru}$ (b)${}_{25}{\text{Mn}}^{+}$

• A. (a)$\pm 2,\sqrt{24},4$; (b)$\pm 3,\sqrt{48},6$
• B. (a)$\pm 3,\sqrt{26},6$; (b)$\pm 2,\sqrt{50},4$
• C. (a)$\pm 2,\sqrt{26},4$; (b)$\pm 2,\sqrt{48},6$
• D. (a)$\pm 3,\sqrt{24},6$; (b)$\pm 3,\sqrt{50},4$

Answer 1

The correct option is A (a)$\pm 2,\sqrt{24},4$; (b)$\pm 3,\sqrt{48},6$

Electronic configuration:

Ru- $\left[Kr\right]4d^{7}5s^1$

4 unpaired electrons, so total spin will be either +2 or -2.

Magnetic moment- $\sqrt{n(n+2)}$

Magnetic moment- $\sqrt{4(4+2)}=\sqrt{24}$

$M{n}^{+}-\left[Ar\right]4s^{1}3d^5$

6 unpaired electrons, so total spin will be either +3 or -3.

Magnetic moment- $\sqrt{6(6+2)}=\sqrt{48}$