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Standard X

Chemistry

Newland Law of Octaves

The electroni...

Question

The electronic spectrum of $[T i (H_{2} O)_{6}]^{3 +}$ shows a single broad peak with a maximum at $20, 300 c m^{- 1} .$ The crystal field stabilization energy $C F S E$ of the complex ion, in $k J m o l^{- 1}$ , is $(1 k J m o l^{- 1} = 83.7 c m^{- 1})$

145.5

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83.7

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97

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242.5

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Solution

The correct option is C $97$

For octahedral,

$C F S E = - 0.4 Δ_{o} = - 0.4 \times 20300 = - 8120 c m^{- 1}$

$C F S E (i n k J) = \frac{8120}{83.7} = 97 k J / m o l$

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Similar questions

Q. Find the crystal field stabilization energy (CFSE) (in kJ/mol) for complex,

{[T i {(H_{2} O)}_{6}]}^{3 +}

. According to CFT, the first absorption maximum is obtained at

20, 3000 c m^{- 1}

for the transition

With the help of CFT number of unpaired electron in a compound can be calculated and we can calculate its paramagnetic moment (due to spin only), by the formula :

μ, = \sqrt{n (n + 2)}

Bohr magneton (BM), where 'n' is the number of unpaired electron in the complex. For spectral analysis the separation between

t_{2 g}

and

e_{g}

orbitals, called ligand field splitting parameter

Δ_{0}

(for octahedral complexes) should be known to us, which can be easily calculated by observing the absorption spectrum of one

e^{-}

complex figure shows the optical absorptions spectrum of the

d^{1}

hexaaqatitanium (III) ion

[T i (H_{2} O)_{6}]^{3 +}

. The CFT assigns the first absorption maximum at 20,300

c m^{- 1}

to the transition

e_{g} \leftarrow t_{2 g}

. For multielectronic

(d^{2} t o d^{10})

system, the calculation of

Δ_{0}

by absorption spectrum is not that easy as the absorption spectrum will also be affected by electron-electron repulsions.

The crystal field stabilization energy (CFSE) for complex given in the passage,

[T i (H_{2} O)_{6}^{3 +}

will be (in kJ / mol) :

Q. Calculate the electron affinity of oxygen atom in gaining two electrons to give the oxide ion

O^{- 2}

from the following data.
Standard heat of formation of

M g O_{(s)} = - 600 k J m o l^{- 1}

Lattice energy of

M g O_{(s)} = - 3860 k J m o l^{- 1}

lonization energy of

M g_{(g)}

to give

M g^{+ 2}

is +2170

k J m o l^{- 1}

Dissociation energy of

O_{2 (g)}

is +494

k J m o l^{- 1}

Heat of sublimation of

M g_{(s)}

is +150

k J m o l^{- 1}

[T i (N C S)_{6}]^{3 -}

ion exhibits a single absorption band at 544 nm. What will be the crystal field splitting energy (in kJ/mol) of the complex ?

(h = 6.626 \times 10^{- 34} J s; c = 3 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} i o n s / m o l e)

Q. The

[T i (N C S)_{6}]^{3 -}

ion exhibits a single absorption band at 544 nm. What will be the crystal field splitting energy

(i n k J m o l^{- 1})

of the complex?

(h = 6.626 \times 10^{- 34} J . s; C = 3.0 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} i o n s / m o l e

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The electronic spectrum of [Ti(H2O)6]3+ shows a single broad peak with a maximum at 20,300 cm−1. The crystal field stabilization energy CFSE of the complex ion, in kJ mol−1 , is (1 kJ mol−1=83.7 cm−1)

The correct option is C 97 For octahedral, CFSE=−0.4 Δo=−0.4×20300=−8120 cm−1 CFSE (in kJ)=812083.7=97 kJ/mol

The electronic spectrum of $[T i (H_{2} O)_{6}]^{3 +}$ shows a single broad peak with a maximum at $20, 300 c m^{- 1} .$ The crystal field stabilization energy $C F S E$ of the complex ion, in $k J m o l^{- 1}$ , is $(1 k J m o l^{- 1} = 83.7 c m^{- 1})$

The correct option is C $97$

For octahedral,

$C F S E = - 0.4 Δ_{o} = - 0.4 \times 20300 = - 8120 c m^{- 1}$

$C F S E (i n k J) = \frac{8120}{83.7} = 97 k J / m o l$