The electronic structure of four elements a, b, c, d respectively are:
(a) 1 $s^{2}$
(b) 1 $s^{2}$ 2 $s^{2}$ 2 $p^{2}$
(c) 1 $s^{2}$ 2 $s^{2}$ 2 $p^{5}$
(d) 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$
The tendency to form eIectrovalent bond will be largest in :

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Solution

The correct option is C C
Element 'C' is fluorine which is the most electronegative element. It forms electrovalent bond with metal, by gaining one electron to complete its octet. In other options they have to accept more than one electron to get octet configuration. Hence, option C is the correct answer.

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