The electrons- identified by quantum number n and l- - iii n-3- l-2 and iv n-3- l-1 -i n-4- l-1ii n-4-1-0 iii n-3- l-2 andCan be placed in order of increasing energy- from lowest to highest asA- iv - ii - iii - iB- ii - iv - i - iiiC- i - iii - ii - iv D- iii - i - iv - ii

The correct option is C (i) lt; (iii) lt; (ii) lt; (iv) First just calculate the (n + l) values of all. (i) n + l = 4 + 1 = 5 (ii) n + l = 4 ...

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Byju's Answer

Standard XII

Chemistry

Aufbau Principle

The electrons...

Question

The electrons, identified by quantum number n and l,
(i) n = 4, l = 1(ii) n = 4, l = 0(iii) n = 3, l = 2 and (iv) n = 3, l = 1
Can be placed in order of increasing energy, from lowest to highest as

(iv) < (ii) < (iii) < (i)

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(ii) < (iv) < (i) < (iii)

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(i) < (iii) < (ii) < (iv)

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(iii) < (i) < (iv) < (ii)

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Solution

The correct option is C
(i) < (iii) < (ii) < (iv)

First just calculate the (n + l) values of all.

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Similar questions

Q. The electrons identified by quantum numbers n and l
(i) n=4, l=1
(ii) n=4, l=0
(iii) n=3, l=2
(iv) n=3, l=1
can be placed in order of increasing energy from the lowest to highest, as

Q. The electrons, identified by quantum numbers

n

and

l

,
(i)

n = 4, l = 1

(ii)

n = 4, l = 0

(iii)

n = 3, l = 2

and
(iv)

n = 3

l = 1

can be placed in order of increasing energy from the lowest to highest, as:

Q. The electrons, identified by quantum numbers

n

and

l

(i) n = 4, l = 1, (i i) n = 4, l = 0, (i i i) n = 3, l = 2, (i v) n = 3, l = 1

can be placed in order of increasing energy, from the lowest to highest, as:

The electrons, identiﬁed by quantum numbers n and l
(i) n = 4, l = 1 (ii) n = 4, l = 0 (iii) n = 3, l = 2 (iv) n = 3, l = 1
can be placed in order of increasing energy, from the lowest to highest, as

Q. The electrons, identified by quantum numbers

n

and

l

(i)

n = 4, l = 1

, (ii)

n = 4, l = 0

(iii)

n = 3, l = 2

(iv)

n = 3, l = 1

can be place in order of increasing energy, from the lowest to highest, as:

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The electrons, identified by quantum number n and l, (i) n = 4, l = 1(ii) n = 4, l = 0(iii) n = 3, l = 2 and (iv) n = 3, l = 1 Can be placed in order of increasing energy, from lowest to highest as

The correct option is C (i) < (iii) < (ii) < (iv) First just calculate the (n + l) values of all.

The electrons, identified by quantum number n and l,
(i) n = 4, l = 1(ii) n = 4, l = 0(iii) n = 3, l = 2 and (iv) n = 3, l = 1
Can be placed in order of increasing energy, from lowest to highest as

The correct option is C
(i) < (iii) < (ii) < (iv)

First just calculate the (n + l) values of all.