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Byju's Answer

Standard XII

Physics

Binding Energy

The electrons...

Question

The electrons identified by quantum numbers n and l
(i) n=4, l=1
(ii) n=4, l=0
(iii) n=3, l=2
(iv) n=3, l=1
can be placed in order of increasing energy from the lowest to highest, as

(iv) < (ii) < (iii) <(i)

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(ii) < (iv) < (i) < (iii)

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(i) < (iii) < (ii) < (iv)

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(iii) < (i) < (iv) < (ii)

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Solution

The correct option is A (iv) < (ii) < (iii) <(i)
(i)4p
(ii)4s
(iii)3d
(iv)3p
order of increasing energy is 3p < 4s < 3d < 4p.

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Similar questions

Q. The electrons, identified by quantum number n and l,
(i) n = 4, l = 1

(ii) n = 4, l = 0

(iii) n = 3, l = 2

and

(iv) n = 3, l = 1
Can be placed in order of increasing energy, from lowest to highest as

Q. The electrons, identified by quantum number n and l,
(i) n = 4, l = 1

(ii) n = 4, l = 0

(iii) n = 3, l = 2

and

(iv) n = 3, l = 1
Can be placed in order of increasing energy, from lowest to highest as

Q. The electrons are identified by quantum number n and l. Place them in increasing order of energy:
(i) n = 4, l = 1
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Q. The electrons, identified by quantum numbers

n

and

l

,
(i)

n = 4, l = 1

(ii)

n = 4, l = 0

(iii)

n = 3, l = 2

and
(iv)

n = 3

l = 1

can be placed in order of increasing energy from the lowest to highest, as:

The electrons, identiﬁed by quantum numbers n and l
(i) n = 4, l = 1 (ii) n = 4, l = 0 (iii) n = 3, l = 2 (iv) n = 3, l = 1
can be placed in order of increasing energy, from the lowest to highest, as

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The electrons identified by quantum numbers n and l (i) n=4, l=1 (ii) n=4, l=0 (iii) n=3, l=2 (iv) n=3, l=1 can be placed in order of increasing energy from the lowest to highest, as

The correct option is A (iv) < (ii) < (iii) <(i)(i)4p (ii)4s (iii)3d (iv)3p order of increasing energy is 3p < 4s < 3d < 4p.

The electrons identified by quantum numbers n and l
(i) n=4, l=1
(ii) n=4, l=0
(iii) n=3, l=2
(iv) n=3, l=1
can be placed in order of increasing energy from the lowest to highest, as

The correct option is A (iv) < (ii) < (iii) <(i)
(i)4p
(ii)4s
(iii)3d
(iv)3p
order of increasing energy is 3p < 4s < 3d < 4p.