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Question

The electrons, identified by quantum numbers n and l
(i) n = 4, l = 1 (ii) n = 4, l = 0 (iii) n = 3, l = 2 (iv) n = 3, l = 1
can be placed in order of increasing energy, from the lowest to highest, as


A

(iv) < (ii) < (iii) < (i)

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B

(ii) < (iv) < (i) < (iii)

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C

(i) < (iii) < (ii) < (iv)

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D

(iii) < (i) < (iv) < (ii)

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Solution

The correct option is A

(iv) < (ii) < (iii) < (i)


(i) n = 4, l = 1 4p-orbital

(ii) n = 4, l = 0 4s-orbital

(iii) n = 3, l = 2 3d-orbital

(iv) n = 3, l = 1 3p-orbital

According to Aufbau principle, energies of above mentioned orbitals are in the order of

(iv) 3p < (ii) 4s < (iii) 3d < (i) 4p


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