Question

The electrophile involved in Reimer-Tiemann reaction is:

• A. $:\text{CHCl}$
• B. $\stackrel{⨁}{\text{C}}{\text{HCl}}_2$
• C. $:{\text{CCl}}_2$
• D. $\cdot {\text{CCl}}_3$

Answer 1

The correct option is C

$:{\text{CCl}}_2$

${\text{CHCl}}_3\stackrel{\stackrel{\ominus }{\text{O}\text{H}}}{\to }\stackrel{\ominus }{\text{C}}{\text{Cl}}_3\stackrel{-\text{C}{\text{l}}^{\ominus }}{\to }\underset{\begin{array}{c}\text{acts as an}\\ \text{Electrophile}\end{array}}{{\text{:CCl}}_2}$