The electrophile involved in the above reaction is :

dichloro carbene (: $C C l_{2}$ )

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dichloro methyl cation $(\oplus C H C l_{2})$

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Formyl cation $(\oplus C H O)$

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tri chloro methyl anion $(⊖ C \oplus C l_{3})$

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Solution

The correct option is A
dichloro carbene (: $C C l_{2}$ )

It is the Reiman-Tiemann reaction. The electrophile is formed by the reaction. The trichloromethylcarbanion undergoes an \(\alpha\ -) elimination to gives us the dichlorocarbene:

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Similar questions

C_{6} H_{5} O H + C H C l_{3} + N a O H \to S a l i c y l a l d e h y d e

$C_{6} H_{5} O H + C H C l_{3} + N a O H \to$ Salicylaldehyde. The electrophile involved in the above reaction is.

C_{6} H_{5} O H + C H C l_{3} + N a O H \to C_{6} H_{4} (C H O) O H

N a_{2} C r O F_{4}

C r (H_{2} O)_{6} C l_{3}

The IUPAC name of the compound $(C H_{3})_{2} C H C H_{2} C H_{2} C l$ is?

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