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Question

The electrostatic attracting force on a small sphere of charge 0.2μC due to another small sphere of charge 0.4μC in air is 0.4N. The distance between the two spheres is

A
43.2×106m
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B
42.4×103m
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C
18.1×103m
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D
19.2×106m
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Solution

The correct option is B 42.4×103m
Here, q1=0.2μC=0.2×106C,q2=.0.4μC=0.4×106C,F=0.4N
As F=q1q24πε0r2
r2=q1q24πε0F=0.2×106×0.4×106×9×1090.4=1.8×103
r=(1.8×103)1/2=0.0424m=42.4×103m

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