The element in the first row and third column of the inverse of the matrix ⎡⎢⎣123012001⎤⎥⎦, is
A
−2
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B
0
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C
1
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D
none of these
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Solution
The correct option is A1 A=⎡⎢⎣123012001⎤⎥⎦ Here, |A|=1 The cofactor of element C31=3×1−2×2=7 The element a13 in the adjoint matrix =C31 So, a13=7 in adjoint matrix Since, |A|=1 , so a13=7 will be the a13 of inverse matrix