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Anomalous Behaviour of Fluorine

The element t...

Question

The element that oxidizes water to $O_{2}$ with a large evolution of heat is:

A

F_{2}

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B

{C l}_{2}

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C

B r_{2}

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D

I_{2}

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Solution

The correct option is B $F_{2}$
$F_{2}$ is the most powerful oxidizing
agent and evolves large amount
of heat due to the formation of H - bond
with $H_{2} O$ ( It is also the most electronegative element )

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Similar questions

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

Q. Consider the following orders –
(1)

F_{2} > C l_{2} > B r_{2} > I_{2} :

boiling point
(2)

F_{2} > C l_{2} > B r_{2} > I_{2} :

oxidizing nature
(3)

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Acidic nature
(8)

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Oxidizing nature
Then calculate

(x^{2} + y^{2})

x

is correct order and

y

is incorrect order.

Q. Increasing oxidising nature of

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

.
if true enter 1, else enter 0.

Q. Assertion :In organic layer test ,

C l_{2}

water is added to the sodium extract which oxidizes

B r^{θ}

I^{θ}

B r_{2}

I_{2}

respectively. Reason: Reduction potential of

C l_{2}

is greater than that of

B r_{2}

I_{2}

.

B r_{2}

I_{2}

C l_{2}

C l_{2}

has a reduction potential higher than that of

B r_{2}

I_{2}

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