Question

The element which accepts electrons readily to form anion belongs to

• A. VII A group and second period
• B. VII A group and third period
• C. O group and third period
• D. VIA group and third period

Answer 1

The correct option is B

VII A group and third period

Explanation for correct answer:

The tendency to accept an electron readily and turn into an anion is called oxidising property or electron affinity.

B)The element that contains highest Electron affinity in the periodic table is Chlorine(Cl).

Chlorine atomic number - 17

Electronic configuration - $1s^{2}2s^{2}2p^{6}3s^{2}3p^5$- It has 7 electrons in the valence shell, 1 electron less than the Inert gas(Argon) configuration.It readily accepts one electron.

Chlorine has valence electrons in 3rd shell - It belongs to 3rd period.

Chlorine has seven valence electrons - It belongs to VIIA group (valence electrons= group number).

Explanation for incorrect answer:

A) Chlorine - belongs to VIIA group but not second period.

C)Chlorine - belongs to third period but not 0 group.

D) Chlorine- belongs to third period but not sixth group.

Hence, b) is correct option - The element that accepts electron readily(Chlorine) belongs to VIIA group and third period.