Question

The element with $Z=106$ belongs to :

• A. $3^{rd}$ period
• B. $5^{th}$ period
• C. $7^{th}$ period
• D. $6^{th}$ period

Answer 1

Answer: (C)

$7^{th}$ period

$Z=106$ is seaborgium and its electronic configaration is $\left(Rn\right)5f^{14}6d^{4}7s^2$. as the differenting electron enter into $7s$, 7 is the principle quantum number which represents the number of period to which the element belongs hence, the element belongs to 7th period.