The elements having lowest and highest oxidation number respectively are:

S c, F e

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S c, M n

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A g, M n

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F e, M n

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Solution

The correct option is C $A g, M n$

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Similar questions

V^{2 +} < C r^{2 +} < M n^{2} < F e^{2 +}

N i^{2 +} < C o^{2 +} < F e^{2 +} < M n^{2 +}

C o^{3 +} < F e^{3 +} < C r^{3 +} < S c^{3 +}

S c < T i < C r < M n

For the four successive transition elements (Cr, Mn, Fe and Co), what is the order of stability of their +2 states?

(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

E^{0} M^{2 +} / M

C u^{+}, F e^{2 +}, M n^{2 +}, C r^{3 +}, S c^{3 +}, T i^{4 +}

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