Question

The elevation of a cloud is ${60}^0$ above the horizon. A thunder is heard 8 s after the observation of lighting. The speed of sound is 330 $m{s}^{-1}$. The vertical height of cloud from ground is

• A. 2826 m
• B. 2682 m
• C. 2286 m
• D. 2068 m

Answer 1

The correct option is C 2286 m

Given:

$\theta ={60}^{\circ }$

$t=8\sec$

$v=330m/s$

To find:

The vertical height of cloud from the ground

Solution:

We know that,

$d=v\left(t\right)$

So,

$d=\left(330\right)8$

$d=2640m$

Now, from the right triangle,

$\sin \theta =\frac{opposite}{hypotnuse}$

$\sin \theta =\frac{h}{d}$

$h=2640\left(0.866\right)$

$h=2286m$

Hence the correct answer is option (C)