The elevator shown in figure is descending with an acceleration of 2m/s2. The mass of the block A is 0.5kg. What force is exerted by the block A on the block B ?
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Solution
From the free body diagram R+0.5×2−w=0
⇒R=w−0.5×2
=0.5(10−2)=4N
So, the force exerted by the block A on the block B, is 4N