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Question

The elevator shown in the figure is descending with an acceleration of 2 m/s2. The mass of the block A=0.5 kg. The force exerted by the block A on the block B is (take g=10 m/s2)

A
2 N
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B
4 N
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C
6 N
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D
8 N
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Solution

The correct option is B 4 N
Let A applies a force R on B, then B also applies an opposite and equal force R on A.
The FBDs of the block are as shown

Considering the frame of reference as elevator, a pseudoforce ma will be acting on A upwards where m is mass of block A, therefore
mgR=ma
R=m(ga)=0.5[102]=4 N

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