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Question

The elevator shown in the figure is descending with an acceleration of 2 ms2. The mass of the block A=0.5 kg. The force exerted by the block A on the block B is (g=10 ms2)

A
2 N
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B
4 N
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C
6 N
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D
8 N
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Solution

The correct option is B 4 N
When the elevator moves downward with acceleration a, net normal (N) force acting by A on B will be,

N=mA(ga)=0.5(102)=4 N

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