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Question

The ellipse x2a2+y2b2=1 and hyperbola x2A2y2B2=1 are having a same foci and length of minor axis of ellipse is same as the conjugate axis of the hyperbola. If e1 & e2 are the eccentricities of ellipse and hyperbola respectively, then the value of 1e21+1e22 is

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is B 2
Since, ellipse and hyperbola has the same foci, therefore the major axis of ellipse will be x axis.
Now, ae1=Ae2; b=B
e21a2=A2e22
e21b21e21=e22B2e221
11e211=111e22
1e21+1e22=2

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