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Question

The ellipse x2a2+y2b2=1 passes through the point (3,1) and has the eccentricity 25. Then the major axis of the ellipse has the length:

A
425
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B
823
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C
423
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D
825
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Solution

The correct option is D 823
Given ellipse passes through (3,1)
9a2+1b2=1...(1)
Also eccentricity is e=25
Using, e2=1b2a2b2a2=35..(2)
Solving (1) and (2) we get, a=423
Hence, length of major axis is =2a=823

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