The EMF of a cell - Zn - 2H- - Zn2- 0-1 M - H2 1 atm is 0-28V at 25-C- Calculate pH of the solution at the hydrogen gas electrode-Given that - E-Zn2- - Zn - - 0-76 V-

Zn + 2H^⊕ → Zn^2+ (0.1 M) + H_2 (1 atm) E_cell = 0.28 V E^⊖_cell = (E^⊖_c E^⊖_a)_red = 0 ( 0.76) V = 0.76 V . E_ ...

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Nernst Equation

The EMF of a ...

Question

The EMF of a cell : $Z n + 2 H^{+} \to Z n^{2 +} (0.1 M) + H_{2} (1 a t m)$ is $0.28$ V at $25^{\circ} C$ . Calculate pH of the solution at the hydrogen gas electrode.
Given that : $E_{(Z n^{2 +} | Z n)}^{⊖} = - 0.76 V$ .

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