Question

The emf of cell at 298 K is:

[Given : $\frac{2.303\times RT}{F}=0.06]$

• A. 1.07 V
• B. 1.04 V
• C. 1.03 V
• D. 1.06 V

Answer 1

The correct option is A 1.07 V

According to Nernst equation,

$E_{cell}=E_{cell}^0-\frac{0.06}{n}log\frac{\left[Z{n}^{2+}\right]}{\left[C{u}^{++}\right]}$

$n=2$

$=1.1-0.06\times \frac{1}{2}=1.1-0.03=1.07$V.

Thus, the correct option is $A$