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EMF

The emf of th...

Question

The emf of the cell is given as:
$N i | N i^{- 2} (1.0) | | A u^{+ 3} (0.1 M) | A u$
$[E^{o}$ for $N i^{- 2} / N i = - 0.25 V, E^{o}$ for $A u^{+ 3} / A u = 1.50 V]$

+ 1.25 V

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- 1.75 V

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+ 1.75 V

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+ 2.50 V

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Solution

The correct option is B $+ 1.75 V$
$N i | N i_{(1.0)}^{2 -} | | A u_{(0.1 M)}^{3 +} | A u$
$E M F = E_{R H S}^{o} - E_{L H S}^{o}$
$= 1.5 - (- 0.25)$
$= 1.5 + 0.25 = 1.75 V$

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The EMF of the cell : Ni(s) | Ni²⁺ (1.0M) || Au ³⁺(1.0M) | Au (s) is

[ given E^o_Ni²⁺_/Ni -0.25V; E° _Au³⁺_{/ Au} = +1.50V ]

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N i / {N i}^{+ 2} (0 / 1 M) | | {A u}^{+ 3} (1.0 M) / A u

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{[E}_{N i / N i^{+ 2}}^{o} = 0.25 V, E_{A u / A u^{+ 3}}^{o} = - 1.5 V]

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