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Nernst Equation

The EMF of th...

Question

The EMF of the cell $M | M^{n +} (0.2 M) | | H^{+} (1 M) | H_{2} (g) (1 a t m)$ , Pt at $25^{\circ} C$ is 0.81 V. Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76 V.

n = 2

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n = 3

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n = 1

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None of these

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Solution

The correct option is A $n = 2$
$M | M^{n +} (0.2 M) | | H^{+} (1 M) | H_{2} (g) (1 a t m)$
As we know,
$E = E^{0} - (0.0591 / n) l o g M^{n +}$
$0.81 = 0.76 - (0.0591 / n) l o g M^{n +}$
$n = 2$
so valency of metal is $2$ .

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M | M^{n +} (0.02 M) | | H^{+} (1 M) | H_{2} (g) (1 atm), P t

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M + N^{+ 2} \to M^{+ 2} + N

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