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Nernst Equation

The EMF of th...

Question

The EMF of the cell $M | M^{n +} (0.01 M) | | H^{+} (1 M) | H_{2} (g) (1 a t m),$ Pt at $25^{o}$ C is $0.82$ V. Calculate the valency of the metal if the standard oxidation potential of the metal is $0.76$ V.
Take $\frac{2.303 R T}{F} = 0.06$ at $25^{o}$ C.

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Solution

$M^{n +} + {n e}^{-} ⟶ M$
$E_{c e l l} = E_{c e l l}^{0} - \frac{2.303 R T}{n F} l o g$
$\Rightarrow 0.82 = 0.76 - \frac{0.06}{n} l o g 10^{- 2}$
$\Rightarrow n = 2$
$∴$ Valency of the total is $2$ .

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