CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

The EMF of the cell M|Mn+ (0.02 M)||H+ (1 M)|H2 (g)(1 atm),Pt at 25C is 0.81 V. Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76 V.
(Given, log4=0.6)

A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2
MMn++ne ... (1)
2e+2H+H2 ... (2)
If we multiply equation 1 by 2 and 2 by n and add both equation then we get
2M+2nH+2Mn++nH2
E=E0.059nlog[Mn+]2[H+]2n
0.81=(0.76+0)0.0592nlog[0.02]2[1]2n
n=0.0592×0.05log4×104
n=0.59(4+0.6)
n=2
Therefore, valency of metal is 2.

flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon