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Question

The EMF of the cell :
Pt, H2(1atm)|H(aq)AgCl|Ag is 0.27 and 0.26 V at 25C and 35C, respectively. The posituve value of heat of the reaction occurring inside the cell at 25C (inkJK1) is: ( write your answer to nearest integer)

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Solution

(ET)p=(0.260.273525)=0.0710VK1[ncell=1]
ΔH=nF[Ecell(at25C)T(ET)p]
ΔH=1×96500[0.27298(0.0110)]
ΔH=1×96500C×0.568VK1=54812JK1
=54.8kJK1

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