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Standard VII

Chemistry

Sub-Atomic Particles

The emission ...

Question

The emission of an $α - p a r t i c l e$ :

reduces the mass of nuclei by 4 units and increases its atomic number 2

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increases the mass of nuclei by 4 units and increases its atomic number 2

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increases the mass of nuclei by 4 units and decreases its atomic number 2

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reduces the mass of nuclei by 4 units and decreases its atomic number 2

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Solution

The correct option is B reduces the mass of nuclei by 4 units and decreases its atomic number 2
The emission of an particle reduces the mass of nuclei by 4 units and decreases its atomic number by 2.
$_{Z}^{A} X \to_{Z - 2}^{A - 4} Y +_{2}^{4} H e$

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Similar questions

Q. STATEMENT - 1 :

_{Z} X^{A}

undergoes 2

α

decays, 2

β

decays (negative

β

) and 2 decays. As a result the daughter product is

_{Z - 2} Y^{A - 8} .

STATEMENT -2 : In

α

decay the mass number decreases by 4 unit and atomic number decreases by 2 unit. In

β

decay (negative

β

) the mass number remains unchanged and atomic number increases by 1 unit. In

γ

decay, mass number and atomic number remains unchanged.

Q. Assertion :

_{Z} X^{4}

undergoes

2 α - d e c a y s, 2 β - d e c a y s

(negative

β

), and

2 γ - d e c a y s

. As a result, the daughter product is

_{z - 2} Y^{A - B}

Reason: In

α - d e c a y

, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In

β - d e c a y

(negative

β

), the mass number remains unchanged and atomic number increases by 1 unit. In

γ - d e c a y

, mass number and atomic number remain unchanged.

Q. Assertion :

{_{z} X}^{A}

undergoes

2

α

- decays,

2

β

- decays (negative

β

) and

2

γ

-decays. As a result , the daughter product is

{_{z - 2} Y}^{A - 8}

Reason: In

α

- decay, the mass number decreases by

4

unit and atomic number decreases by

2

unit. In

β

- decay (negative

β

), the mass number remains unchanged and atomic number increaess by

1

unit. In

γ

-decay, mass number and atomic number remain unchanged

Q. An element

X

decays, first by positron emission and then two

α

-particles are emitted in successive radioactive decay. If the product nuclei has a mass number

229

and atomic number

89

, the mass number and atomic number of element X are

Q. Assertion :When there is an emission of

α

-particles, new elements is displaced two group of the parent element. Reason: Atomic mass decreases by 2 units due to

α

-particle emission.

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The emission of an α−particle:

The correct option is B reduces the mass of nuclei by 4 units and decreases its atomic number 2The emission of an particle reduces the mass of nuclei by 4 units and decreases its atomic number by 2.AZX→A−4Z−2Y+42He

The emission of an $α - p a r t i c l e$ :

The correct option is B reduces the mass of nuclei by 4 units and decreases its atomic number 2
The emission of an particle reduces the mass of nuclei by 4 units and decreases its atomic number by 2.
$_{Z}^{A} X \to_{Z - 2}^{A - 4} Y +_{2}^{4} H e$