Multi-Electron Configurations and Orbital Diagrams
The emission ...
Question
The emission spectrum of hydrogen is found to satisfy the expression for the energy change △E (in joules) such that △E=2.18×18−18(1n21−1n22)J where n1= 1, 2, 3, .......and n2 = 2, 3, 4. The spectral lines corresponds to Paschen series if :
A
n1=1 and n2=2,3,4
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B
n1=3 and n2=4,5,6
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C
n1=1 and n2=3,4,5
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D
n1=2 and n2=3,4,5
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Solution
The correct option is Bn1=3 and n2=4,5,6 In the emission spectra of hydrogen atom, Paschen series is the one where the transition from higher energy states to third energy state takes place.