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Question

The empirical formula of a compound containing 47.9 % potassium, 5.5 % beryllium and 46.6 % fluorine by mass is

[At. weight of Be = 9; F= 19; K=39]

A
K2BeF2
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B
KBeF4
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C
K2Be2F4
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D
K2BeF4
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Solution

The correct option is C K2BeF4
Element Percentage composition Atomic weight Relative No. of atoms Simplest ratio
Potassium 47.9 39 47.9/39 = 1.21.2/0.6 = 2
Beryllium 5.5 9 5.5/9 = 0.60.6/0.6 = 1
Fluorine 46.6 19 46.6/19 = 2.42.4/0.6 = 4
Hence, empirical formula is K2BeF4.

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