The empirical formula of a compound is $C H_{2} O . 0.0835 m o l$ of the compound contains $1.0 g$ of hydrogen. Molecular formula of
the compound is:

C_{5} H_{10} O_{5}

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C_{6} H_{12} O_{6}

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C_{4} H_{8} O_{8}

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C_{3} H_{6} O_{3}

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Solution

The correct option is B $C_{6} H_{12} O_{6}$
$Calculating molecular formula of the compound$

The empirical formula is $C H_{2} O .$

And molecular formula can be written as

$= (C H_{2} O)_{n}$

$= C_{n} H_{2 n} O_{n}$

Now, $0.0835 m o l$ of compound contains $1 g$ of hydrogen.

Thus $1 m o l$ of compound contains
$\frac{1}{0.0835} i . e ., 12 g o f H .$

$12 g$ of hydrogen signifies that in 1 mol compound, 12 hydrogen atom are present.

Since molecular formula is $C_{n} H_{2 n} O_{n}$

Thus, $2 n = 12$

$n = 6$

Hence, molecular formula is $C_{6} H_{12} O_{6}$

So, option (b) is the correct answer.

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