Question

The empirical formula of a compound is $C{H}_{2}O$. If $0.0835$ moles of the compound contains $1$ g of hydrogen, the molecular formula of the compound is:

• A. $C_2{H}_4{O}_2$
• B. $C_3{H}_6{O}_3$
• C. $C_6{H}_{12}{O}_6$
• D. $C_4{H}_8{O}_4$

Answer 1

Answer: (C)

$C_6{H}_{12}{O}_6$

$0.0835$ mol of the compound contains $1$ g of hydrogen.
$\therefore$ $1$ mol contains $=\frac{1}{0.0835}=$$12$ g $=12$ moles of Hydrogen atom.

$\text{Molecular formula}=(\text{Empirical formula}{)}_n$

So, $2n=12$

$\therefore$ the $n$ factor is $6$.

Hence, the molecular formula is $=C_6{H}_{12}{O}_6$.