The empirical formula of a compound is $C H_{2} O$ and its vapour density is $30$ . The molecular formula of the compound is :

C_{3} H_{6} O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{4} O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{4} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $C_{2} H_{4} O_{2}$
$M W = 2 \times V . D . = 2 \times 30 = 60 g .$

Empirical formula weight (E.F.W) $= C H_{2} O = 12 + 2 + 16 = 30$ g.

$n = \frac{M . W .}{E . F . W} = 2$

Molecular formula $= (C H_{2} O)_{2}$ $= C_{2} H_{4} O_{2}$

Option B is correct.

Suggest Corrections

Similar questions

Q. The molecular formula of a compound whose empirical formula is

C H_{2} O

and vapour density is 30 is

Empirical formula of a compound is CH₂O. If its empirical formula mass is equal to its vapour density. Calculate the molecular formula of the compound.

Q. Empirical formula of compound is

C H_{2} O

. If is vapour density is 90, then molecular formula of compound is:

Q. The empirical formula of a compound is

C H_{2} O

. If the vapour density is 60, what would be the molecular formula of the compound?

Q. An organic compound has an empirical formula,

C H_{2} O

. Its vapour density is

45

. The molecular formula of the compound is:

Join BYJU'S Learning Program

The empirical formula of a compound is CH2O and its vapour density is 30. The molecular formula of the compound is :

The correct option is D C2H4O2MW=2×V.D.=2×30=60g.Empirical formula weight (E.F.W) =CH2O=12+2+16=30 g.n=M.W.E.F.W=2Molecular formula =(CH2O)2=C2H4O2Option B is correct.

The empirical formula of a compound is $C H_{2} O$ and its vapour density is $30$ . The molecular formula of the compound is :

The correct option is D $C_{2} H_{4} O_{2}$
$M W = 2 \times V . D . = 2 \times 30 = 60 g .$

Empirical formula weight (E.F.W) $= C H_{2} O = 12 + 2 + 16 = 30$ g.

$n = \frac{M . W .}{E . F . W} = 2$

Molecular formula $= (C H_{2} O)_{2}$ $= C_{2} H_{4} O_{2}$

Option B is correct.