The empirical formula of a given compound with a molar mass of $28 g m o l^{- 1}$ is $C H_{2}$ . If its molecular formula is $C_{x} H_{y}$ then, $x * y = ?$

Open in App

Solution

$C H_{2} : 1 \times 12 g m o l^{- 1} + 2 \times 1 g m o l^{- 1} = 14 g m o l^{- 1}$

$n = \frac{M o l e c u l a r M a s s}{E m p i r i c a l M a s s} =$ $\frac{28}{14} = 2$

Then, Molecular formula $= C_{2} H_{4}$ i.e., $x = 2; y = 4$
So, $x * y = 2 * 4 = 8$

Suggest Corrections

Similar questions

Q. The empirical formula of a compound is

C H_{2}

. One mole of this compound has a mass of

42

g. Its molecular formula is:

A compound has an empirical formula of C₂HBr. If the molar mass of the compound is 314.7 g/mol, what is the molecular formula of the compound? (Atomic mass of Br = 80g/mol)

Q. What is the molecular formula of fructose if its molar mass is

180. g / m o l

, and its empirical formula is

C H_{2} O

Q. A hydrocarbon has an empirical formula of

C H

and a molar mass of

26 g / m o l

. What is the molecular formula of this compound?

Q. The empirical formula of an organic compound is

C H_{2}

. The mass of

1

mole of it is

42

g. The molecular formula of the compound is :

Join BYJU'S Learning Program

The empirical formula of a given compound with a molar mass of 28 g mol−1 is CH2. If its molecular formula is CxHy then, x∗y=?

CH2:1×12 g mol−1+2×1 g mol−1=14 g mol−1 n=Molecular MassEmpirical Mass=2814=2 Then, Molecular formula =C2H4 i.e., x=2;y=4 So, x∗y=2∗4=8

The empirical formula of a given compound with a molar mass of $28 g m o l^{- 1}$ is $C H_{2}$ . If its molecular formula is $C_{x} H_{y}$ then, $x * y = ?$

$C H_{2} : 1 \times 12 g m o l^{- 1} + 2 \times 1 g m o l^{- 1} = 14 g m o l^{- 1}$

$n = \frac{M o l e c u l a r M a s s}{E m p i r i c a l M a s s} =$ $\frac{28}{14} = 2$

Then, Molecular formula $= C_{2} H_{4}$ i.e., $x = 2; y = 4$
So, $x * y = 2 * 4 = 8$