The empirical formula of a molecule with molar mass 180g is $C H_{2} O$ . Calculate its molecular formula.

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Solution

n= $\frac{m o l a r m a s s}{e m p i r i c a l f o r m u l a m a s s}$

$= \frac{180}{12 + 2 + 16} = 6$

$∴$ The molecular formula is $(C H_{2} O) * 6 = C_{6} H_{12} O_{6}$

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The empirical formula of a molecule with molar mass 180g is CH2O. Calculate its molecular formula.

n= molar massempirical formula mass=18012+2+16=6∴ The molecular formula is (CH2O)∗6=C6H12O6

The empirical formula of a molecule with molar mass 180g is $C H_{2} O$ . Calculate its molecular formula.

n= $\frac{m o l a r m a s s}{e m p i r i c a l f o r m u l a m a s s}$

$= \frac{180}{12 + 2 + 16} = 6$

$∴$ The molecular formula is $(C H_{2} O) * 6 = C_{6} H_{12} O_{6}$