The empirical formula of a monobasic acid is ${C H}_{2} O$ . The vapour density of its ethyl ester is $44$ . What is the Molecular formula of the acid?

C_{2} H_{4} O_{2}

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{C H}_{2} O_{2}

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C_{2} H_{2} O_{2}

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C_{3} H_{6} O_{3}

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Solution

The correct option is A $C_{2} H_{4} O_{2}$
Empirical formula $C H_{2} O \to w e i g h t = 12 + 2 + 16 = 30 g m$
Molecular mass of acid=(Molecular mass of ethyl ester)-(Molecular weight of $C_{2} H_{5}$ )+(Atomic mass of $H$ atom)
$= (2 \times V \cdot D) - (2 \times 12 + 5 \times 1) + 1$
$= 88 - 29 + 1 = 60$
$∴$ Molecular formula $= \frac{M o l e c u l a r W e i g h t}{E m p i r i c a l W e i g h t} \times E m p i r i c a l F o r m u l a$
$= \frac{60}{30} \times C (H_{2} O) = C_{2} H_{4} O_{2}$

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