The empirical formula of a monobasic acid is $C H_{2} O$ .The vapour density of its ester is $44$ . Mlecular formula of the acid?

C_{2} H_{4} O_{2}

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C H_{2} O_{2}

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C_{2} H_{2} O_{2}

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C_{3} H_{6} O_{3}

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Solution

The correct option is A $C_{2} H_{4} O_{2}$
Given the vapour density of ester= $44$
So molecular weight of ester= $44 \times 2 = 88$
$\Rightarrow$ Given, empirical formula of acid= $(C H_{2} O)$ ; weight= $30$
$\Rightarrow$ Molecular formula of acid= $(C H_{2} O)_{n}$ ; weight= $n \times 30$
$\Rightarrow C_{2} H_{4} O_{2} \Rightarrow n = 2$
Because the ester formed $C H_{2} O H |$
$C H_{2} O H$

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The empirical formula of a monobasic acid is CH2O.The vapour density of its ester is 44. Mlecular formula of the acid?

The correct option is A C2H4O2Given the vapour density of ester= 44So molecular weight of ester= 44×2=88⇒ Given, empirical formula of acid= (CH2O); weight= 30⇒ Molecular formula of acid= (CH2O)n; weight= n×30⇒C2H4O2⇒n=2Because the ester formed CH2OH| CH2OH

The empirical formula of a monobasic acid is $C H_{2} O$ .The vapour density of its ester is $44$ . Mlecular formula of the acid?