The empirical formula of a non-electrolyte is $C H_{2} O$ . A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is:

C_{2} H_{4} O_{2}

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C_{3} H_{6} O_{3}

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C_{5} H_{10} O_{5}

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C_{4} H_{8} O_{4}

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Solution

The correct option is D $C_{4} H_{8} O_{4}$
Solutions having same osmotic pressure, at a given temperature, have same concentration.
Concentration of compound $=$ concentration of glucose
$\frac{6}{M \times 1} = 0.05$
$M = \frac{6}{0.05} = 120$
$(C H_{2} O) = 12 + 2 + 16 = 30$
$n = \frac{m o l e c u l a r m a s s}{e m p i r i c a l f o r m u l a m a s s} = \frac{120}{30} = 4$
Hence, Molecular formula $(C H_{2} O)_{4} = C_{4} H_{8} O_{4}$

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